66=(22/7)r^2

Solution for 66=(22/7)r^2 equation:

66=(22/7)r^2

We move all terms to the left:

66-((22/7)r^2)=0


Domain of the equation: 7)r^2)!=0

r!=0/1

r!=0

r∈R


We add all the numbers together, and all the variables

-((+22/7)r^2)+66=0

We multiply all the terms by the denominator


-((+22+66*7)r^2)=0


We calculate terms in parentheses: -((+22+66*7)r^2), so:

(+22+66*7)r^2

We add all the numbers together, and all the variables

484r^2

Back to the equation:

-(484r^2)


a = -484; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-484)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$r=\frac{-b}{2a}=\frac{0}{-968}=0$